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NEET 2010 (AIPMT, Prelims) · Progressive Wave Equation

Progressive Wave Equation question from NEET 2010 (AIPMT, Prelims)

Q91NEET 2010 · AIPMT · PRELIMSMedium

Progressive Wave Equation

A transverse wave is represented by

y = Asin(ω\omegat −- kx). For what value of the wavelength is the wave velocity equal to the maximum particle velocity?

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Answer: (c)

  1. Wave velocity v=ωk=ωλ2πv = \frac{\omega}{k} = \frac{\omega\lambda}{2\pi}; maximum particle velocity =Aω= A\omega
  2. ωλ2π=Aω⇒λ=2πA\frac{\omega\lambda}{2\pi} = A\omega \Rightarrow \lambda = 2\pi A
  3. So the answer is (c) 2πA2\pi A.
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