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JEE Main 2026 (5 Apr, Shift 1) · Progressive Wave Equation

Progressive Wave Equation question from JEE Main 2026 (5 Apr, Shift 1)

Q7JEE Main 2026 · 5 APR · SHIFT 1Easy

Progressive Wave Equation

A transverse wave on a string is described by $y = 3\sin(36t + 0.018x + \pi/4)$ , where $x, y$ are in cm and $t$ in seconds. The least distance between the two successive crests in the wave is ______ cm. (Nearest integer)

$(\pi = 3.14)$

Numerical answer type. Work it out, then open the answer.

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Answer: 349

Distance between successive crests is the wavelength $\lambda = \dfrac{2\pi}{k}$ .
$k = 0.018\text{ cm}^{-1}$
$\lambda = \dfrac{2 \times 3.14}{0.018} = 348.9\text{ cm}$
So the answer is $349\text{ cm}$ .

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