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JEE Main 2022 (29 Jul, Shift 1) · Least Count, Vernier Callipers & Screw Gauge

Least Count, Vernier Callipers & Screw Gauge question from JEE Main 2022 (29 Jul, Shift 1)

Q36JEE Main 2022 · 29 JUL · SHIFT 1Medium

Least Count, Vernier Callipers & Screw Gauge

A travelling microscope has 20 divisions per $\text{cm}$ on the main scale while its vernier scale has total 50 divisions and 25 vernier scale divisions are equal to 24 main scale divisions, what is the least count of the travelling microscope?

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Answer: (c)

1 MSD $= \dfrac{1}{20}\text{ cm} = 0.05\text{ cm}$
$25$ VSD $= 24$ MSD, so LC $= \dfrac{1}{25}\text{ MSD} = \dfrac{0.05}{25}$
LC $= 0.002\text{ cm}$ . So the answer is (c).

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