Physics Circle home Student Login

Home›Chapters›Wave Motion PYQs›Progressive Wave Equation›Question 50

JEE Main 2023 (24 Jan, Shift 1) · Progressive Wave Equation

Progressive Wave Equation question from JEE Main 2023 (24 Jan, Shift 1)

Q50JEE Main 2023 · 24 JAN · SHIFT 1Easy

Progressive Wave Equation

A travelling wave is described by the equation

y(x,t)=[0.05sin⁡(8x−4t)]y(x, t) = [0.05\sin(8x - 4t)] m

The velocity of the wave is: [all the quantities are in SI unit]

Show answer and solution

Answer: (d)

  1. k=8 m−1k = 8\text{ m}^{-1}, ω=4 rad/s\omega = 4\text{ rad/s}
  2. v=ωk=48=0.5 m/sv = \dfrac{\omega}{k} = \dfrac{4}{8} = 0.5\text{ m/s}
  3. So the answer is (d) 0.5 m s−10.5\text{ m s}^{-1}.
Report a mistake

More questions on Progressive Wave Equation