A triangular shaped wire carrying 10 A current is placed in a uniform magnetic field of 0.5 T, as shown in figure. The magnetic force on segment CD is (Given BC = CD = BD = 5 cm.) (a) 0.126 N (b) 0.312 N (c) 0.216 N (d) 0.245 N

Answer: (c). Triangle is equilateral, so CD makes 60° with the horizontal field. F = I L B sin 60° = 10×0.05×0.5×0.866 F ≈ 0.216 N So the answer is (c) 0.216 N.

A triangular shaped wire carrying 10 A current is placed in a uniform… | JEE Main 2022 (28 Jul, Shift 2)

Q40JEE Main 2022 · 28 JUL · SHIFT 2Medium

Force on Current-Carrying Conductors

A triangular shaped wire carrying $10\text{ A}$ current is placed in a uniform magnetic field of $0.5\text{ T}$ , as shown in figure. The magnetic force on segment $CD$ is

(Given $BC = CD = BD = 5\text{ cm}$ .)

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Answer: (c)

Triangle is equilateral, so CD makes $60^\circ$ with the horizontal field.
$F = I L B \sin60^\circ = 10\times0.05\times0.5\times0.866$
$F \approx 0.216\text{ N}$
So the answer is (c) 0.216 N.

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