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JEE Main 2026 (2 Apr, Shift 1) · Archimedes' Principle & Floatation

Archimedes' Principle & Floatation question from JEE Main 2026 (2 Apr, Shift 1)

Q4JEE Main 2026 · 2 APR · SHIFT 1Medium

Archimedes' Principle & Floatation

A tub is filled with water and a wooden cube 1010 cm ×10\times 10 cm ×10\times 10 cm is placed in the water. The wooden cube is found to float on the water with a part of it submerged in water. When a metal coin is placed on the wooden cube, the submerged part is increased by 3.873.87 cm. The mass of the metal coin is ________ gram.

(Take water density as 11 g/cm3^{3} and density of wood as 0.40.4 g/cm3^{3})

Numerical answer type. Work it out, then open the answer.

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Answer: 387

  1. Coin weight = extra upthrust = weight of extra water displaced.
  2. Extra displaced volume =10×10×3.87=387= 10 \times 10 \times 3.87 = 387 cm3^{3}.
  3. Mass of coin =387×1=387= 387 \times 1 = 387 g
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