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JEE Main 2025 (22 Jan, Shift 2) · Centripetal Acceleration & Force

Centripetal Acceleration & Force question from JEE Main 2025 (22 Jan, Shift 2)

Q8JEE Main 2025 · 22 JAN · SHIFT 2Difficult

Centripetal Acceleration & Force

A tube of length 1 m is filled completely with an ideal liquid of mass 2 M, and closed at both ends. The tube is rotated uniformly in horizontal plane about one of its ends. If the force exerted by the liquid at the other end is F then angular velocity of the tube is FαM\sqrt{\frac{F}{\alpha M}} in SI unit. The value of α\alpha is _________.

Numerical answer type. Work it out, then open the answer.

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Answer: 1

  1. The end wall must supply the centripetal force for the whole liquid column.
  2. Element dm=2MLdxdm = \frac{2M}{L}dx at distance xx needs dm ω2xdm\,\omega^2 x.
  3. F=∫0L2MLω2x dx=Mω2L=Mω2F = \int_0^L \frac{2M}{L}\omega^2 x\,dx = M\omega^2 L = M\omega^2 (with L=1L = 1 m).
  4. ω=FM⇒α=1\omega = \sqrt{\frac{F}{M}} \Rightarrow \alpha = 1
  5. Answer: α=1\alpha = 1.
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