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JEE Main 2025 (22 Jan, Shift 2) · Bernoulli's Equation

Bernoulli's Equation question from JEE Main 2025 (22 Jan, Shift 2)

Q9JEE Main 2025 · 22 JAN · SHIFT 2Difficult

Bernoulli's Equation

Figure

A tube of length LL is shown in the figure. The radius of cross section at the point (1)(1) is 2 cm and at the point (2) is 1 cm, respectively. If the velocity of water entering at point (1) is 2 m/s2\text{ m/s}, then velocity of water leaving the point (2) will be

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Answer: (d)

  1. Continuity: πr12v1=πr22v2⇒v2=(r1r2)2v1\pi r_1^2 v_1 = \pi r_2^2 v_2 \Rightarrow v_2 = \left(\frac{r_1}{r_2}\right)^2 v_1
  2. v2=(21)2(2)=8 m/sv_2 = \left(\frac{2}{1}\right)^2 (2) = 8\text{ m/s}
  3. So the answer is (d) 8 m/s.
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