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JEE Main 2002 (AIEEE) · Beats

Beats question from JEE Main 2002 (AIEEE)

Q73JEE Main 2002 · AIEEEEasy

Beats

A tuning fork arrangement (pair) produces $4$ beats/sec with one fork of frequency $288\text{ cps}$ A little wax is placed on the unknown fork and it then produces $2$ beats/sec. The frequency of the unknown fork is

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Answer: (b)

4 beats with 288 cps, so $n = 292$ or $284\text{ cps}$ .
Wax lowers $n$ , and the beats fall to 2, so $n$ was above 288.
$292 \to 290\text{ cps}$ gives 2 beats.
So the answer is (b) $292\text{ cps}$ .

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