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MHT CET 2025 (25 Apr, Shift 2) · Beats

Beats question from MHT CET 2025 (25 Apr, Shift 2)

Q19MHT CET 2025 · 25 APR · SHIFT 2Medium

Beats

A tuning fork gives 5 beats per second with 40 cm length of sonometer wire. If the length of the wire is shortened by 1 cm, the number of beats is still the same. The frequency of the fork is

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Answer: (b)

$f \propto \dfrac{1}{L}$ : 40 cm wire gives $n - 5$ , 39 cm wire gives $n + 5$ .
$(n - 5) \times 40 = (n + 5) \times 39$
$40n - 200 = 39n + 195 \Rightarrow n = 395\text{ Hz}$
So the answer is (b) 395 Hz.

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