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JEE Main 2021 (27 Aug, Shift 2) · Organ Pipes & Resonance Tube

Organ Pipes & Resonance Tube question from JEE Main 2021 (27 Aug, Shift 2)

Q81JEE Main 2021 · 27 AUG · SHIFT 2Easy

Organ Pipes & Resonance Tube

A tuning fork is vibrating at 250 Hz. The length of the shortest closed organ pipe that will resonate with the tuning fork will be __________ cm. (Take speed of sound in air as 340 ms ${}^{-1}$ )

Numerical answer type. Work it out, then open the answer.

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Answer: 34

Shortest closed pipe: $L=\frac{\lambda}{4}=\frac{v}{4f}$ .
$L=\frac{340}{4\times250}=0.34\text{ m}$
$L=34\text{ cm}$

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