A tuning fork of frequency 220 Hz produces sound waves of wavelength 1.5 m in air at N.T.P. The increase in wavelength when the temperature of air is 27 is nearly (√((300)/(273)) = 1.05) (a) 0.06 m (b) 0.10 m (c) 0.09 m (d) 0.07 m

Answer: (d). Frequency fixed, so λ ∝ v ∝ √(T). λ' = 1.5 × √(300/273) = 1.5 × 1.05 ≈ 1.575 m (exact root 1.048 gives 1.572 m). Increase ≈ 0.07 m. So the answer is (d) 0.07 m.

A tuning fork of frequency 220 Hz produces sound waves of wavelength… | MHT CET 2023 (12 May, Shift 2)

Q18MHT CET 2023 · 12 MAY · SHIFT 2Medium

Speed of Waves

A tuning fork of frequency $220\text{ Hz}$ produces sound waves of wavelength $1.5\text{ m}$ in air at N.T.P. The increase in wavelength when the temperature of air is $27^\circ\text{C}$ is nearly $\left(\sqrt{\frac{300}{273}} = 1.05\right)$

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Answer: (d)

Frequency fixed, so $\lambda \propto v \propto \sqrt{T}$ .
$\lambda' = 1.5 \times \sqrt{300/273} = 1.5 \times 1.05 \approx 1.575$ m (exact root 1.048 gives 1.572 m).
Increase $\approx 0.07$ m.
So the answer is (d) 0.07 m.

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Speed of Waves question from MHT CET 2023 (12 May, Shift 2)

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