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JEE Main 2019 (12 Apr, Shift 2) · Organ Pipes & Resonance Tube

Organ Pipes & Resonance Tube question from JEE Main 2019 (12 Apr, Shift 2)

Q103JEE Main 2019 · 12 APR · SHIFT 2Medium

Organ Pipes & Resonance Tube

A tuning fork of frequency 480 Hz is used in an experiment for measuring speed of sound (v) in air by resonance tube method. Resonance is observed to occur at two successive lengths of the air column, l1 = 30 cm and l2 = 70 cm. Then, v is equal to -

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Answer: (b)

Successive resonances differ by $\frac{\lambda}{2}$ : $70 - 30 = 40$ cm, so $\lambda = 0.8$ m.
$v = n\lambda = 480 \times 0.8 = 384$ m s $^{-1}$
So the answer is (b) 384 m s $^{-1}$ .

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