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NEET 2010 (AIPMT, Prelims) · Beats

Beats question from NEET 2010 (AIPMT, Prelims)

Q66NEET 2010 · AIPMT · PRELIMSEasy

Beats

A tuning fork of frequency 512 Hz makes 4 beats per second with the vibrating string of a piano. The beat frequency decreases to 2 beats per sec when the tension in the piano string is slightly increased. The frequency of the piano string before increasing the tension was

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Answer: (d)

String frequency $= 512 \pm 4 = 516$ or $508\text{ Hz}$ .
Increasing tension raises the string frequency, and the beats fall to 2.
So the string was below 512: $508 \to 510\text{ Hz}$ .
So the answer is (d) 508 Hz.

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