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MHT CET 2026 (20 Apr, Shift 1) · Organ Pipes & Resonance Tube

Organ Pipes & Resonance Tube question from MHT CET 2026 (20 Apr, Shift 1)

Q22MHT CET 2026 · 20 APR · SHIFT 1Medium

Organ Pipes & Resonance Tube

A tuning fork of frequency ' $n$ ' is held near the open end of a tube which is dipped in water and length of the tube is adjusted until resonance occurs. If the two shortest lengths that produce resonance are $l_1$ and $l_2$ , the speed of sound in air is (neglect end correction)

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Answer: (a)

Successive resonating lengths of a closed tube differ by half a wavelength: $l_2 - l_1 = \frac{\lambda}{2}$ .
$\lambda = 2(l_2 - l_1)$ , so $v = n\lambda = 2n(l_2 - l_1)$
So the answer is (a) $2n(l_2 - l_1)$ .

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