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JEE Main 2003 (AIEEE) · Beats

Beats question from JEE Main 2003 (AIEEE)

Q72JEE Main 2003 · AIEEEEasy

Beats

A tuning fork of known frequency $256\text{ Hz}$ makes $5$ beats per second with the vibrating string of a piano. The beat frequency decreases to $2$ beats per second when the tension in the piano string is slightly increased. The frequency of the piano string before increasing the tension was

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Answer: (c)

String frequency $= 256 \pm 5\text{ Hz}$ .
Increasing tension raises the string frequency, and the beats fall from 5 to 2.
So the string was below 256: $251 \to 254\text{ Hz}$ .
So the answer is (c) $256 - 5\text{ Hz}$ .

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