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JEE Main 2022 (28 Jun, Shift 2) · Rotational Kinematics & Dynamics

Rotational Kinematics & Dynamics question from JEE Main 2022 (28 Jun, Shift 2)

Q35JEE Main 2022 · 28 JUN · SHIFT 2Medium

Rotational Kinematics & Dynamics

A uniform disc with mass M = 4 kg and radius R = 10 cm is mounted on a fixed horizontal axle as shown in figure. A block with mass m = 2 kg hangs from a massless cord that is wrapped around the rim of the disc. During the fall of the block, the cord does not slip and there is no friction at the axle. The tension in the cord is ____________ N.

(Take g = 10 ms−2{}^{-2})

Figure

Numerical answer type. Work it out, then open the answer.

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Answer: 10

  1. a=mgm+M/2=2×102+2=5 m s−2a = \frac{mg}{m + M/2} = \frac{2\times10}{2 + 2} = 5\text{ m s}^{-2}
  2. T=m(g−a)=2(10−5)=10 NT = m(g - a) = 2(10 - 5) = 10\text{ N}
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