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NEET 2013 · Work by a Constant Force

Work by a Constant Force question from NEET 2013

Q19NEET 2013Easy

Work by a Constant Force

A uniform force of (3i^+j^)\left(3\hat{i} + \hat{j}\right) newton acts on a particle of mass 2 kg. Hence the particle is displaced from position (2i^+k^)\left(2\hat{i} + \hat{k}\right) metre to position (4i^+3j^−k^)\left(4\hat{i} + 3\hat{j} - \hat{k}\right) metre. The work done by the force on the particle is

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Answer: (c)

  1. s⃗=(4−2)i^+3j^+(−1−1)k^=2i^+3j^−2k^\vec{s} = (4-2)\hat{i} + 3\hat{j} + (-1-1)\hat{k} = 2\hat{i} + 3\hat{j} - 2\hat{k} m
  2. W=F⃗⋅s⃗=3(2)+1(3)+0(−2)=9W = \vec{F}\cdot\vec{s} = 3(2) + 1(3) + 0(-2) = 9 J (mass is not needed)
  3. So the answer is (c) 9 J.
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