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NEET 1991 (AIPMT) · Moving Charge in a Magnetic Field

Moving Charge in a Magnetic Field question from NEET 1991 (AIPMT)

Q133NEET 1991 · AIPMTEasy

Moving Charge in a Magnetic Field

A uniform magnetic field acts right angles to the direction of motion of electrons. As a result, the electron moves in a circular path of radius 2 cm2\text{ cm}. If the speed of electrons is doubled, then the radius of the circular path will be

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Answer: (c)

  1. r=mvqB⇒r∝vr = \dfrac{mv}{qB} \Rightarrow r \propto v
  2. Speed doubled ⇒r′=2×2=4 cm\Rightarrow r' = 2\times 2 = 4\text{ cm}
  3. So the answer is (c) 4.0 cm4.0\text{ cm}.
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