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MHT CET 2020 (19 Oct, Shift 2) · Speed of Waves

Speed of Waves question from MHT CET 2020 (19 Oct, Shift 2)

Q27MHT CET 2020 · 19 OCT · SHIFT 2Easy

Speed of Waves

A uniform metal wire has length $L$ , mass $M$ and density $\rho$ . It is under tension $T$ and $v$ is the speed of transverse wave along the wire. The area of cross-section of the wire is

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Answer: (a)

Mass per unit length $\mu = \rho A$ , so $v = \sqrt{\dfrac{T}{\rho A}}$ .
$v^2 = \dfrac{T}{\rho A} \Rightarrow A = \dfrac{T}{v^2\rho}$
So the answer is (a) $\dfrac{T}{v^2\rho}$ .

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