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Combination of Resistors question from NEET 2024

Q21NEET 2024Medium

Combination of Resistors

A uniform metal wire of length ll has 10 Ω10\ \Omega resistance. Now this wire is stretched to a length 2l2l and then bent to form a perfect circle. The equivalent resistance across any arbitrary diameter of that circle is

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Answer: (a)

  1. Stretching to 2l2l (volume constant): R∝l2R \propto l^2, so R′=4×10=40 ΩR' = 4 \times 10 = 40\ \Omega.
  2. Across a diameter: two halves of 20 Ω20\ \Omega in parallel.
  3. Req=202=10 ΩR_{eq} = \dfrac{20}{2} = 10\ \Omega
  4. So the answer is (a) 10 Ω10\ \Omega.
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