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JEE Main 2019 (10 Jan, Shift 1) · Combination of Resistors

Combination of Resistors question from JEE Main 2019 (10 Jan, Shift 1)

Q61JEE Main 2019 · 10 JAN · SHIFT 1Easy

Combination of Resistors

A uniform metallic wire has a resistance of 18 Ω\Omega and is bent into an equilateral triangle. Then, the resistance between any two vertices of the triangle is -

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Answer: (c)

  1. Each side has 183=6 Ω\dfrac{18}{3} = 6\ \Omega.
  2. Between two vertices: 6 Ω6\ \Omega in parallel with 12 Ω12\ \Omega.
  3. Req=6×1218=4 ΩR_{eq} = \dfrac{6 \times 12}{18} = 4\ \Omega
  4. So the answer is (c) 4 Ω4\ \Omega.
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