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JEE Main 2021 (24 Feb, Shift 2) · Young's Modulus & Elongation

Young's Modulus & Elongation question from JEE Main 2021 (24 Feb, Shift 2)

Q21JEE Main 2021 · 24 FEB · SHIFT 2Easy

Young's Modulus & Elongation

A uniform metallic wire is elongated by 0.04 m when subjected to a linear force F. The elongation, if its length and diameter is doubled and subjected to the same force will be ________ cm.

Numerical answer type. Work it out, then open the answer.

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Answer: 2

  1. Same force and material: ΔL∝Ld2\Delta L \propto \frac{L}{d^2}
  2. Doubling LL and dd: factor =222=12= \frac{2}{2^2} = \frac{1}{2}
  3. ΔL′=0.042=0.02 m=2 cm\Delta L' = \frac{0.04}{2} = 0.02\ \text{m} = 2\ \text{cm}
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