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MHT CET 2026 (14 May, Shift 2) · Speed of Waves

Speed of Waves question from MHT CET 2026 (14 May, Shift 2)

Q10MHT CET 2026 · 14 MAY · SHIFT 2Difficult

Speed of Waves

A uniform rope of mass $0.1$ kg and length $2.5$ m hangs from ceiling. The speed of transverse wave in the rope at upper end and at a point $0.5$ m distance from lower end will be ( $g = 10$ m/s $2$ )

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Answer: (a)

For a hanging rope, at height $y$ above the lower end $v = \sqrt{gy}$ .
Upper end: $y = 2.5$ m, $v = \sqrt{25} = 5$ m/s.
At $y = 0.5$ m: $v = \sqrt{5}$ m/s.
So the answer is (a) $5$ m/s, $\sqrt{5}$ m/s.

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