A uniform wire of length l of weight w is suspended from the roof with a weight of W at the other end. The stress in the wire at l/3 distance from the top is (W/A + (2)/(γ)w/A), where A is the cross sectional area of the wire. The value of γ is ________. Numerical answer type. Work it out, then open the answer.

Answer: 3. Tension at a point = load W + weight of the wire below that point. At l/3 from the top, the wire below is 2l/3 long, weighing 2/3w. Stress = W/A + 2/3w/A, compare with W/A + (2)/(γ)w/A. γ = 3

A uniform wire of length l of weight w is suspended from the roof… | JEE Main 2026 (2 Apr, Shift 1)

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Elastic Behaviour, Stress & Strain

A uniform wire of length $l$ of weight $w$ is suspended from the roof with a weight of $W$ at the other end. The stress in the wire at $\frac{l}{3}$ distance from the top is $\left(\frac{W}{A} + \frac{2}{\gamma}\frac{w}{A}\right)$ , where $A$ is the cross sectional area of the wire. The value of $\gamma$ is ________.

Numerical answer type. Work it out, then open the answer.

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Answer: 3

Tension at a point = load $W$ + weight of the wire below that point.
At $\frac{l}{3}$ from the top, the wire below is $\frac{2l}{3}$ long, weighing $\frac{2}{3}w$ .
Stress $= \frac{W}{A} + \frac{2}{3}\frac{w}{A}$ , compare with $\frac{W}{A} + \frac{2}{\gamma}\frac{w}{A}$ .
$\gamma = 3$

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