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NEET 2026 (Re-neet) · Electric Potential & Equipotentials

Electric Potential & Equipotentials question from NEET 2026 (Re-neet)

Q12NEET 2026 · RE-NEETMedium

Electric Potential & Equipotentials

A unit positive point charge is taken slowly through an infinitesimally thin tube that is inside a charged dielectric sphere of radius RR, having uniform positive charge density ρ\rho, as shown in the figure. The initial and final positions of the charge are marked by AA and BB at distance 2R2R and 3R3R respectively, from the centre of the sphere. In this process, the magnitude of the total work done on the point charge is ρR2nε0\frac{\rho R^2}{n\varepsilon_0}. The value of nn is: ( ε0\varepsilon_0 is the permittivity of vacuum)

Figure

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Answer: (a)

  1. Electric force is conservative, so work by the slow external agent =q(VB−VA)= q(V_B - V_A) for any path, including through the sphere.
  2. Outside the sphere V=Q4πε0rV = \dfrac{Q}{4\pi\varepsilon_0 r} with Q=43πR3ρQ = \dfrac43\pi R^3\rho, so V=ρR33ε0rV = \dfrac{\rho R^3}{3\varepsilon_0 r}.
  3. VA=ρR26ε0V_A = \dfrac{\rho R^2}{6\varepsilon_0}, VB=ρR29ε0V_B = \dfrac{\rho R^2}{9\varepsilon_0}
  4. ∣W∣=ρR2ε0(16−19)=ρR218ε0|W| = \dfrac{\rho R^2}{\varepsilon_0}\left(\dfrac16 - \dfrac19\right) = \dfrac{\rho R^2}{18\varepsilon_0}
  5. So n=18n = 18, answer (a).
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