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MHT CET 2025 (21 Apr, Shift 2) · Vector Basics, Unit Vectors & Components

Vector Basics, Unit Vectors & Components question from MHT CET 2025 (21 Apr, Shift 2)

Q9MHT CET 2025 · 21 APR · SHIFT 2Medium

Vector Basics, Unit Vectors & Components

A unit vector in the direction of resultant vector of A⃗=−2i^+3j^+k^\vec{A} = -2\hat{i} + 3\hat{j} + \hat{k} and B⃗=i^+2j^−4k^\vec{B} = \hat{i} + 2\hat{j} - 4\hat{k} is

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Answer: (d)

  1. A⃗+B⃗=(−2+1)i^+(3+2)j^+(1−4)k^=−i^+5j^−3k^\vec{A} + \vec{B} = (-2 + 1)\hat{i} + (3 + 2)\hat{j} + (1 - 4)\hat{k} = -\hat{i} + 5\hat{j} - 3\hat{k}
  2. Magnitude =1+25+9=35= \sqrt{1 + 25 + 9} = \sqrt{35}
  3. So the answer is (d) −i^+5j^−3k^35\frac{-\hat{i} + 5\hat{j} - 3\hat{k}}{\sqrt{35}}.
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