A varying magnetic flux linking a coil is Φ = xt². If at time t = 3 s, the e.m.f. induced is 9 V then the magnitude of x is (in Wb /s²) (a) 1.5 (b) 0.66 (c) 0.33 (d) 0.75

Answer: (a). e = (dΦ)/(dt) = 2xt At t = 3 s: 9 = 2x × 3 = 6x x = 1.5 Wb/s ² So the answer is (a) 1.5.

A varying magnetic flux linking a coil is Φ = xt². If at time t = 3… | MHT CET 2026 (13 May, Shift 2)

Q13MHT CET 2026 · 13 MAY · SHIFT 2Medium

Magnetic Flux & Faraday's Law

A varying magnetic flux linking a coil is $\Phi = xt^{2}$ . If at time $t = 3$ s, the e.m.f. induced is $9$ V then the magnitude of $x$ is (in Wb $/\text{s}^{2}$ )

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Answer: (a)

$e = \frac{d\Phi}{dt} = 2xt$
At $t = 3$ s: $9 = 2x \times 3 = 6x$
$x = 1.5$ Wb/s $^2$
So the answer is (a) 1.5.

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