A vector A when added to the sum of the vectors (i - 2j + 2k) and (-2i + j - k) gives a unit vector along Y axis. The magnitude of vector A is (a) √(3) (b) √(6) (c) √(8) (d) √(10)

Answer: (b). Sum of the two vectors: (i - 2j + 2k) + (-2i + j - k) = -i - j + k A + (-i - j + k) = j ⇒ A = i + 2j - k |A| = √(1 + 4 + 1) = √(6) So the answer is (b) √(6).

A vector A when added to the sum of the vectors (i - 2j + 2k) and… | MHT CET 2026 (15 Apr, Shift 1)

Q4MHT CET 2026 · 15 APR · SHIFT 1Easy

Vector Basics, Unit Vectors & Components

A vector $\vec{A}$ when added to the sum of the vectors $(\hat{i} - 2\hat{j} + 2\hat{k})$ and $(-2\hat{i} + \hat{j} - \hat{k})$ gives a unit vector along Y axis. The magnitude of vector $\vec{A}$ is

Show answer and solution

Answer: (b)

Sum of the two vectors: $(\hat{i} - 2\hat{j} + 2\hat{k}) + (-2\hat{i} + \hat{j} - \hat{k}) = -\hat{i} - \hat{j} + \hat{k}$
$\vec{A} + (-\hat{i} - \hat{j} + \hat{k}) = \hat{j} \Rightarrow \vec{A} = \hat{i} + 2\hat{j} - \hat{k}$
$|\vec{A}| = \sqrt{1 + 4 + 1} = \sqrt{6}$
So the answer is (b) $\sqrt{6}$ .

Report a mistake

Vector Basics, Unit Vectors & Components question from MHT CET 2026 (15 Apr, Shift 1)

More questions on Vector Basics, Unit Vectors & Components