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MHT CET 2025 (22 Apr, Shift 1) · Banking of Roads & Bridges

Banking of Roads & Bridges question from MHT CET 2025 (22 Apr, Shift 1)

Q3MHT CET 2025 · 22 APR · SHIFT 1Easy

Banking of Roads & Bridges

A vehicle is moving with a constant speed of 10 m/s10\text{ m/s} in a circular horizontal track of radius 20 m. A bob is suspended from the roof of a vehicle by a massless string. The angle made by the string with the vertical will be (acceleration due to gravity, g=10 m/s2g = 10\text{ m/s}^2)

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Answer: (a)

  1. In the car frame, the bob is in equilibrium under TT, mgmg and centrifugal mv2r\frac{mv^2}{r}.
  2. tan⁡θ=v2rg=10020×10=0.5\tan\theta = \frac{v^2}{rg} = \frac{100}{20 \times 10} = 0.5
  3. So the answer is (a) tan⁡−1(0.5)\tan^{-1}(0.5).
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