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MHT CET 2020 (16 Oct, Shift 1) · Work-Energy Theorem

Work-Energy Theorem question from MHT CET 2020 (16 Oct, Shift 1)

Q17MHT CET 2020 · 16 OCT · SHIFT 1Medium

Work-Energy Theorem

A vehicle of mass $m$ is moving with momentum $p$ on a rough horizontal road. The coefficient of friction between the tyres and the horizontal road is $\mu$ . The stopping distance is ( $g =$ acceleration due to gravity)

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Answer: (b)

Friction work removes all KE: $\mu mg\,s = \frac{p^2}{2m}$ .
$s = \frac{p^2}{2\mu g m^2}$
So the answer is (b) $\frac{p^2}{2\mu g m^2}$ .

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