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JEE Main 2024 (5 Apr, Shift 2) · Least Count, Vernier Callipers & Screw Gauge

Least Count, Vernier Callipers & Screw Gauge question from JEE Main 2024 (5 Apr, Shift 2)

Q21JEE Main 2024 · 5 APR · SHIFT 2Medium

Least Count, Vernier Callipers & Screw Gauge

A vernier callipers has 20 divisions on the vernier scale, which coincides with $19$ th division on the main scale. The least count of the instrument is $0.1\text{ mm}$ . One main scale division is equal to ________ mm.

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Answer: (b)

$20\text{ VSD} = 19\text{ MSD} \Rightarrow$ LC $= \dfrac{1\text{ MSD}}{20}$
$\dfrac{1\text{ MSD}}{20} = 0.1$ mm $\Rightarrow 1\text{ MSD} = 2$ mm
So the answer is (b) 2.

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