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MHT CET 2025 (19 Apr, Shift 2) · Spring Systems

Spring Systems question from MHT CET 2025 (19 Apr, Shift 2)

Q31MHT CET 2025 · 19 APR · SHIFT 2Medium

Spring Systems

A vertical spring oscillates with period 6 second with mass mm is suspended from it. When the mass is at rest, the spring is stretched through a distance of (Take, acceleration due to gravity, g=π2=10 m/s2g = \pi^2 = 10\text{ m/s}^2)

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Answer: (d)

  1. At rest kx=mgkx = mg, so mk=xg\frac{m}{k} = \frac{x}{g} and T=2πxgT = 2\pi\sqrt{\frac{x}{g}}.
  2. x=gT24π2=10×364×10=9x = \frac{gT^2}{4\pi^2} = \frac{10\times36}{4\times10} = 9 m
  3. So the answer is (d) 9 m.
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