Physics Circle home Student Login

Home›Chapters›Fluid Statics PYQs›Archimedes' Principle & Floatation›Question 1

MHT CET 2026 (12 May, Shift 1) · Archimedes' Principle & Floatation

Archimedes' Principle & Floatation question from MHT CET 2026 (12 May, Shift 1)

Q1MHT CET 2026 · 12 MAY · SHIFT 1Easy

Archimedes' Principle & Floatation

A vessel contains oil (density=0.6= 0.6 g/cm3^{3}) over mercury (density=13.6= 13.6 g/cm3^{3}). A homogeneous sphere floats with half its volume immersed in mercury and the remaining half in oil. The density of the material of the sphere in g/cm3^{3} is

Show answer and solution

Answer: (c)

  1. Weight = total upthrust: Vρg=V2ρHgg+V2ρoilgV\rho g = \dfrac{V}{2}\rho_{Hg} g + \dfrac{V}{2}\rho_{oil} g.
  2. ρ=13.6+0.62=7.1\rho = \dfrac{13.6 + 0.6}{2} = 7.1 g/cm3^{3}
  3. So the answer is (c) 7.17.1.
Report a mistake

More questions on Archimedes' Principle & Floatation