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MHT CET 2026 (11 Apr, Shift 1) · Archimedes' Principle & Floatation

Archimedes' Principle & Floatation question from MHT CET 2026 (11 Apr, Shift 1)

Q2MHT CET 2026 · 11 APR · SHIFT 1Easy

Archimedes' Principle & Floatation

A vessel contains oil (density =0.8= 0.8 gm/cm3/\text{cm}^{3}) over mercury (density =13.6= 13.6 gm/cm3/\text{cm}^{3}). A homogeneous sphere floats with half of its volume immersed in mercury and the other half in oil. The density of the material of the sphere in gm/cm3/\text{cm}^{3} is

Figure

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Answer: (b)

  1. Weight = total upthrust: Vρg=V2ρHgg+V2ρoilgV\rho g = \dfrac{V}{2}\rho_{Hg} g + \dfrac{V}{2}\rho_{oil} g.
  2. ρ=13.6+0.82=7.2\rho = \dfrac{13.6 + 0.8}{2} = 7.2 g/cm3^{3}
  3. So the answer is (b) 7.27.2.
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