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MHT CET 2026 (11 Apr, Shift 1) · Gas Laws & Ideal Gas Equation

Gas Laws & Ideal Gas Equation question from MHT CET 2026 (11 Apr, Shift 1)

Q8MHT CET 2026 · 11 APR · SHIFT 1Medium

Gas Laws & Ideal Gas Equation

A vessel has 66 gram of hydrogen at pressure PP and temperature 500500 K. A small hole is made in it so that hydrogen leaks out. How much hydrogen leaks out if the final pressure is P2\frac{P}{2} and the temperature falls to 300300 K?

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Answer: (d)

  1. PV=mMRTPV = \dfrac{m}{M}RT with VV fixed ⇒m∝PT\Rightarrow m \propto \dfrac{P}{T}.
  2. m2=6×P/2P×500300=6×12×53=5m_2 = 6 \times \dfrac{P/2}{P} \times \dfrac{500}{300} = 6 \times \dfrac{1}{2} \times \dfrac{5}{3} = 5 g
  3. Leaked mass =6−5=1= 6 - 5 = 1 g
  4. So the answer is (d) 11 gram.
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