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JEE Main 2026 (24 Jan, Shift 1) · Special Purpose Diodes

Special Purpose Diodes question from JEE Main 2026 (24 Jan, Shift 1)

Q14JEE Main 2026 · 24 JAN · SHIFT 1Medium

Special Purpose Diodes

A voltage regulating circuit consisting of Zener diode, having break-down voltage of 10 V and maximum power dissipation of 0.4 W, is operated at 15 V. The approximate value of protective resistance in this circuit is $\underline{\qquad\quad}\,\Omega$ .

Numerical answer type. Work it out, then open the answer.

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Answer: 125

Maximum Zener current: $I = \frac{P}{V_Z} = \frac{0.4}{10} = 0.04$ A
Drop across protective resistor: $15 - 10 = 5$ V
$R = \frac{5}{0.04} = 125\ \Omega$

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