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MHT CET 2026 (20 May, Shift 1) · Moving Coil Galvanometer, Ammeter & Voltmeter

Moving Coil Galvanometer, Ammeter & Voltmeter question from MHT CET 2026 (20 May, Shift 1)

Q12MHT CET 2026 · 20 MAY · SHIFT 1Medium

Moving Coil Galvanometer, Ammeter & Voltmeter

A voltmeter with series resistance $R$ has a range $(0 - V_1)$ volt. With a series resistance of $4R$ , its range becomes $(0 - V_2)$ volt. The relation between $V_1$ and $V_2$ is

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Answer: (b)

Range $V = I_g(G + R_{series})$ .
$V_1 = I_g(G + R)$ , $V_2 = I_g(G + 4R)$
$4V_1 = I_g(4G + 4R) > I_g(G + 4R) = V_2$ since $G > 0$ .
So the answer is (b) $V_2 < 4V_1$ .

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