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JEE Main 2026 (4 Apr, Shift 2) · Types of Flow, Reynolds Number & Continuity

Types of Flow, Reynolds Number & Continuity question from JEE Main 2026 (4 Apr, Shift 2)

Q5JEE Main 2026 · 4 APR · SHIFT 2Easy

Types of Flow, Reynolds Number & Continuity

A water spray gun is attached to a hose of cross sectional area 30 cm230\text{ cm}^2. The gun comprises of 10 perforations each of cross sectional area of 15 mm215\text{ mm}^2. If the water flows in the hose with the speed of 50 cm/s50\text{ cm/s}, calculate the speed at which the water flows out from each perforation. (Neglect any edge effects)

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Answer: (b)

  1. Continuity: A1v1=navA_1 v_1 = n a v (all perforations together).
  2. A1v1=30 cm2×50 cm/s=1500 cm3/s=1.5×10−3 m3/sA_1 v_1 = 30\text{ cm}^2 \times 50\text{ cm/s} = 1500\text{ cm}^3/\text{s} = 1.5\times10^{-3}\text{ m}^3/\text{s}
  3. na=10×15 mm2=150 mm2=1.5×10−4 m2na = 10 \times 15\text{ mm}^2 = 150\text{ mm}^2 = 1.5\times10^{-4}\text{ m}^2
  4. v=1.5×10−31.5×10−4=10 m/sv = \dfrac{1.5\times10^{-3}}{1.5\times10^{-4}} = 10\text{ m/s}
  5. So the answer is (b) 10 m/s10\text{ m/s}.
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