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NEET 1994 (AIPMT) · Stationary Waves & Vibrating Strings

Stationary Waves & Vibrating Strings question from NEET 1994 (AIPMT)

Q116NEET 1994 · AIPMTEasy

Stationary Waves & Vibrating Strings

A wave of frequency 100 Hz100\text{ Hz} travels along a string towards its fixed end. When this wave travels back, after reflection, a node is formed at a distance of 10 cm10\text{ cm} from the fixed end. The speed of the wave (incident and reflected) is

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Answer: (a)

  1. The fixed end is a node; the next node is λ2\frac{\lambda}{2} away.
  2. λ2=10 cm⇒λ=0.2 m\frac{\lambda}{2} = 10\text{ cm} \Rightarrow \lambda = 0.2\text{ m}.
  3. v=nλ=100×0.2=20 m/sv = n\lambda = 100 \times 0.2 = 20\text{ m/s}.
  4. So the answer is (a) 20 m/s20\text{ m/s}.
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