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JEE Main 2008 (AIEEE) · Progressive Wave Equation

Progressive Wave Equation question from JEE Main 2008 (AIEEE)

Q94JEE Main 2008 · AIEEEEasy

Progressive Wave Equation

A wave travelling along the xx-axis is described by the equation y(x,t)=0.005cos⁡(αx−βt).y(x, t) = 0.005\cos(\alpha x - \beta t). If the wavelength and the time period of the wave are 0.08 m0.08\text{ m} and 2.0 s2.0\text{ s}, respectively, then α\alpha and β\beta in appropriate units are

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Answer: (a)

  1. α=k=2πλ=2π0.08=25π m−1\alpha = k = \dfrac{2\pi}{\lambda} = \dfrac{2\pi}{0.08} = 25\pi\text{ m}^{-1}
  2. β=ω=2πT=2π2.0=π rad/s\beta = \omega = \dfrac{2\pi}{T} = \dfrac{2\pi}{2.0} = \pi\text{ rad/s}
  3. So the answer is (a) α=25.00π\alpha = 25.00\pi, β=π\beta = \pi.
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