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MHT CET 2025 (20 Apr, Shift 2) · Non-Uniform Circular Motion

Non-Uniform Circular Motion question from MHT CET 2025 (20 Apr, Shift 2)

Q6MHT CET 2025 · 20 APR · SHIFT 2Easy

Non-Uniform Circular Motion

A wheel initially at rest, begins to rotate about its axis with constant angular acceleration. If it rotates through an angle θ1\theta_1 in first 2 s and a further angle θ2\theta_2 in the next 2 s, the ratio θ1:θ2\theta_1 : \theta_2 is

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Answer: (d)

  1. From rest: θ=12αt2\theta = \frac{1}{2}\alpha t^2.
  2. θ1=12α(2)2=2α\theta_1 = \frac{1}{2}\alpha(2)^2 = 2\alpha; total in 4 s =12α(4)2=8α= \frac{1}{2}\alpha(4)^2 = 8\alpha.
  3. θ2=8α−2α=6α\theta_2 = 8\alpha - 2\alpha = 6\alpha
  4. So the answer is (d) 1:31 : 3.
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