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JEE Main 2025 (2 Apr, Shift 2) · Rotational Kinematics & Dynamics

Rotational Kinematics & Dynamics question from JEE Main 2025 (2 Apr, Shift 2)

Q21JEE Main 2025 · 2 APR · SHIFT 2Medium

Rotational Kinematics & Dynamics

Figure

A wheel of radius 0.2 m rotates freely about its center when a string that is wrapped over its rim is pulled by force of 10 N as shown in figure. The established torque produces an angular acceleration of 2 rad/s22\text{ rad/s}^{2}. Moment of intertia of the wheel is___________ kg m2\text{kg m}^{2}. (Acceleration due to gravity =10 m/s2= 10\text{ m/s}^{2})

Numerical answer type. Work it out, then open the answer.

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Answer: 1

  1. τ=FR=10×0.2=2 N m\tau = FR = 10\times0.2 = 2\text{ N m}
  2. I=τα=22=1 kg m2I = \frac{\tau}{\alpha} = \frac{2}{2} = 1\text{ kg m}^2
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