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NEET 1994 (AIPMT) · Ohm's Law, Resistivity & Temperature

Ohm's Law, Resistivity & Temperature question from NEET 1994 (AIPMT)

Q78NEET 1994 · AIPMTEasy

Ohm's Law, Resistivity & Temperature

A wire 50 cm50\text{ cm} long and 1 mm21\text{ mm}^{2} in cross-section carries a current of 4 A4\text{ A} when connected to a 2 V2\text{ V} battery. The resistivity of the wire is

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Answer: (b)

  1. R=VI=24=0.5 ΩR = \dfrac{V}{I} = \dfrac{2}{4} = 0.5\ \Omega
  2. ρ=RAl=0.5×1×10−60.5\rho = \dfrac{RA}{l} = \dfrac{0.5 \times 1 \times 10^{-6}}{0.5}
  3. ρ=1×10−6 Ω m\rho = 1 \times 10^{-6}\ \Omega\text{ m}
  4. So the answer is (b) 1×10−6 Ω m1 \times 10^{-6}\ \Omega\text{ m}.
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