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MHT CET 2026 (11 Apr, Shift 2) · Force on Current-Carrying Conductors

Force on Current-Carrying Conductors question from MHT CET 2026 (11 Apr, Shift 2)

Q6MHT CET 2026 · 11 APR · SHIFT 2Medium

Force on Current-Carrying Conductors

A wire AB is carrying steady current I1I_1 and is kept on the table. Another wire CD carrying current I2I_2 is held directly above as shown in figure. When the wire CD is left free and it remains suspended at its position, its mass per unit length is (g=acceleration due to gravity, μ0\mu_0 = permeability of free space)

Figure

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Answer: (a)

  1. Currents in AB and CD are opposite, so CD is repelled upward.
  2. Balance per unit length: μ0I1I22πr=λg\frac{\mu_0 I_1 I_2}{2\pi r} = \lambda g
  3. λ=μ0I1I22πrg\lambda = \frac{\mu_0 I_1 I_2}{2\pi r g}
  4. So the answer is (a).
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