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JEE Main 2004 (AIEEE) · Elastic Potential Energy

Elastic Potential Energy question from JEE Main 2004 (AIEEE)

Q15JEE Main 2004 · AIEEEEasy

Elastic Potential Energy

A wire fixed at the upper end stretches by length $l$ by applying a force $F.$ The work done in stretching is

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Answer: (d)

Force grows linearly from 0 to $F$ during stretching, so average force is $F/2$ .
$W = \dfrac{1}{2}Fl$
So the answer is (d) $\dfrac{Fl}{2}$ .

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