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MHT CET 2025 (20 Apr, Shift 1) · Magnetic Field of Straight Wires

Magnetic Field of Straight Wires question from MHT CET 2025 (20 Apr, Shift 1)

Q23MHT CET 2025 · 20 APR · SHIFT 1Medium

Magnetic Field of Straight Wires

A wire has three different sections as shown in figure. The magnitude of the magnetic field produced at the centre ' OO ' of the semicircle by three sections together is ( μ0=\mu_0 = permeability of free space)

Figure

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Answer: (a)

  1. Straight sections (i) and (iii) lie on the diameter line through O, so they give zero.
  2. Semicircle (ii): B=12⋅μ0I2R=μ0I4RB = \frac{1}{2} \cdot \frac{\mu_0 I}{2R} = \frac{\mu_0 I}{4R}
  3. So the answer is (a) μ0I4R\frac{\mu_0 I}{4R}.
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