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JEE Main 2023 (25 Jan, Shift 2) · Motional EMF

Motional EMF question from JEE Main 2023 (25 Jan, Shift 2)

Q25JEE Main 2023 · 25 JAN · SHIFT 2Easy

Motional EMF

A wire of length 1m moving with velocity 8 m/s at right angles to a magnetic field of 2T. The magnitude of induced emf, between the ends of wire will be __________.

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Answer: (c)

  1. ε=Blv\varepsilon = Blv
  2. ε=2×1×8=16\varepsilon = 2 \times 1 \times 8 = 16 V
  3. So the answer is (c) 16 V.
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