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JEE Main 2022 (27 Jul, Shift 2) · Stationary Waves & Vibrating Strings

Stationary Waves & Vibrating Strings question from JEE Main 2022 (27 Jul, Shift 2)

Q74JEE Main 2022 · 27 JUL · SHIFT 2Medium

Stationary Waves & Vibrating Strings

A wire of length 30 cm, stretched between rigid supports, has it's nth and (n + 1)th harmonics at 400 Hz and 450 Hz, respectively. If tension in the string is 2700 N, it's linear mass density is ____________ kg/m.

Numerical answer type. Work it out, then open the answer.

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Answer: 3

  1. Fundamental n1=450−400=50 Hzn_1 = 450 - 400 = 50\text{ Hz}.
  2. v=2Ln1=2×0.3×50=30 m/sv = 2Ln_1 = 2\times0.3\times50 = 30\text{ m/s}
  3. μ=Tv2=2700900=3 kg/m\mu = \dfrac{T}{v^2} = \dfrac{2700}{900} = 3\text{ kg/m}
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