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MHT CET 2019 (3 May, Shift 1) · Young's Modulus & Elongation

Young's Modulus & Elongation question from MHT CET 2019 (3 May, Shift 1)

Q25MHT CET 2019 · 3 MAY · SHIFT 1Easy

Young's Modulus & Elongation

A wire of length LL and radius rr is rigidly fixed at one end. On stretching the other end of the wire with a force FF, the increase in length is ll. If another wire of the same material but double the length and radius is stretched with a force 2F2F, then increase in length is

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Answer: (d)

  1. Same material: ΔL=FLπr2Y∝FLr2\Delta L = \frac{FL}{\pi r^2 Y} \propto \frac{FL}{r^2}
  2. ΔL′l=2F×2L(2r)2⋅r2FL=44=1\frac{\Delta L'}{l} = \frac{2F \times 2L}{(2r)^2} \cdot \frac{r^2}{FL} = \frac{4}{4} = 1
  3. So the answer is (d) ll.
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